# for-loop - python-带for循环的格式化输出

``````
def perfect_square(num):

for number in range(1, num, 1):

square = number ** 2

# print(square, end='')

print("the perfect squares from {} are: {}".format(num, square))

``````

``````
Enter a positive integer: 10

the perfect squares from 10 are: 81

``````

``````
def perfect_square(num):

import math

for number in range(1, num, 1):

square = number ** 2

# print(square, end='')

print("the perfect squares from {} are: {}".format(num, square))

``````

``````
Enter a positive integer: 10

the perfect squares from 10 are: 1

the perfect squares from 10 are: 4

the perfect squares from 10 are: 9

the perfect squares from 10 are: 16

the perfect squares from 10 are: 25

the perfect squares from 10 are: 36

the perfect squares from 10 are: 49

the perfect squares from 10 are: 64

the perfect squares from 10 are: 81

``````
``````
The required output needs to look like this

Enter a positive integer: 10

The perfect squares for the number 10 are: 1, 4, 9

``````

``````
import math

for number in range(1, num):

if number ** .05 % 1 == 0:

print("the perfect squares from {} are: {}".format(num, number))

``````

``````
Enter a positive integer: 10

the perfect squares from 10 are: 1

``````

``````
def find_squares(x):

return_value = []

for i in range(1, x + 1):

# Note that x**0.5 is the squareroot of x

if i**0.5 % 1 == 0:

return_value.append(i)

return return_value

``````

``````
import math

def findSquares(x):

for i in range(1, x+1):

if math.sqrt(i).is_integer():

print("one perfect number is:" + str(i))

``````